6b^2-18b-168=0

Solution for 6b^2-18b-168=0 equation:

6b^2-18b-168=0

a = 6; b = -18; c = -168;
Δ = b2-4ac
Δ = -182-4·6·(-168)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-66}{2*6}=\frac{-48}{12}
=-4
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+66}{2*6}=\frac{84}{12}
=7
$